Java Program To Check if a number is Armstrong or not.

A number is armstrong if the sum of the cubes of digit of number is equal to the number.
ex- 407 = 4*4*4 + 0*0*0 + 7*7*7

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import java.util.Scanner; public class ArmstrongNum{ public static void main(String[] args){ Scanner in = new Scanner(System.in); System.out.println("Enter a number which you want to check whether that is armstrong or not: "); int n = in.nextInt(); int a = n, r=0, s=0; while(a!=0){ r = a%10; a = a/10; s = s + r*r*r; } if(s==n){ System.out.println("Number "+n+" is an armstrong number."); }else{ System.out.println("Number "+n+" is not an armstrong number."); } } }

Output

Enter a number which you want to check whether that is armstrong or not: 407 Number 407 is an armstrong number.